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Regular Expression
Test String
Substitution
Parentheses01
down vote accepted You need to create a set of escaped (with \) parentheses (that match the parentheses) and a group of regular parentheses that create your capturing group: var regExp = /\(([^)]+)\)/; var matches = regExp.exec("I expect five hundred dollars ($500)."); //matches[1] contains the value between the parentheses console.log(matches[1]); Breakdown: \( : match an opening parentheses ( : begin capturing group [^)]+: match one or more non ) characters ) : end capturing group \) : match closing parenthesesComments
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Cheat Sheet
| Character classes | |
|---|---|
| . | any character except newline |
| \w \d \s | word, digit, whitespace |
| \W \D \S | not word, digit, whitespace |
| [abc] | any of a, b, or c |
| [^abc] | not a, b, or c |
| [a-g] | character between a & g |
| Anchors | |
| ^abc$ | start / end of the string |
| \b | word boundary |
| Escaped characters | |
| \. \* \\ | escaped special characters |
| \t \n \r | tab, linefeed, carriage return |
| \u00A9 | unicode escaped © |
| Groups & Lookaround | |
| (abc) | capture group |
| \1 | backreference to group #1 |
| (?:abc) | non-capturing group |
| (?=abc) | positive lookahead |
| (?!abc) | negative lookahead |
| Quantifiers & Alternation | |
| a* a+ a? | 0 or more, 1 or more, 0 or 1 |
| a{5} a{2,} | exactly five, two or more |
| a{1,3} | between one & three |
| a+? a{2,}? | match as few as possible |
| ab|cd | match ab or cd |
